# Line slope calculator 4x-3y=12

**Straight line given by points A[3; 0] and B[6; 4]**

## Calculation:

**Slope-intercept form of line:**y = 1.3333x-4

**Canonical form of the line equation:**4x-3y-12 = 0

**Parametric form of the line equation:**

x = 3t+3

y = 4t ; t ∈ R

**Slope:**m = 1.3333

**Slope angle of line: φ =**53°7'48″ = 0.9273 rad

**X intercept:**x

_{0}= 3

**Y intercept:**y

_{0}= q = -4

**Distance line from the origin:**d

_{0}= 2.4

**The length of the segment AB: |AB| =**5

**Vector: AB =**(3; 4)

**Normal vector: n =**(4; -3)

**Midpoint of the segment AB: M =**[4.5; 2]

**Perpendicular Bisector equation:**3x+4y-21.5 = 0

**Vector OA = (3; 0) ; |OA| = 3**

**Vector OB = (6; 4) ; |OB| = 7.2111**

**Scalar product OA .OB = 18**

**Angle ∠ AOB = 33°41'24″ = 0.588 rad**