Question

### Gauthmathier4007

Grade 10 · 2020-10-29

Find all real values of x such that f(x)=0.

f(x)=x^{2}-5x+6

f(x)=x^{2}-5x+6

Good Question (64)

Answer

4.6(848) votes

### Gauthmathier3722

Grade 10 · 2020-10-29

Answer

x=2 or x=3.

Explanation

Solution For each function, set f(x)=0 and solve for x.

x^{2}-5x+6=0 Set f(x) equal to 0.

(x-2)(x-3)=0 Factor.

x-2=0\rightarrow x=2 Set 1st factor equal to 0.

x-3=0\rightarrow x=3 Set 2nd factor equal to 0.

So, f(x)=0 when x=2 or x=3.

x^{2}-5x+6=0 Set f(x) equal to 0.

(x-2)(x-3)=0 Factor.

x-2=0\rightarrow x=2 Set 1st factor equal to 0.

x-3=0\rightarrow x=3 Set 2nd factor equal to 0.

So, f(x)=0 when x=2 or x=3.

Thanks (61)

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