# Line slope calculator 5x-2y=38

**Straight line given by points A[8; 1] and B[10; 6]**

## Calculation:

**Slope-intercept form of line:**y = 2.5x-19

**Canonical form of the line equation:**5x-2y-38 = 0

**Parametric form of the line equation:**

x = 2t+8

y = 5t+1 ; t ∈ R

**Slope:**m = 2.5

**Slope angle of line: φ =**68°11'55″ = 1.1903 rad

**X intercept:**x

_{0}= 7.6

**Y intercept:**y

_{0}= q = -19

**Distance line from the origin:**d

_{0}= 7.0564

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(2; 5)

**Normal vector: n =**(5; -2)

**Midpoint of the segment AB: M =**[9; 3.5]

**Perpendicular Bisector equation:**2x+5y-35.5 = 0

**Vector OA = (8; 1) ; |OA| = 8.0623**

**Vector OB = (10; 6) ; |OB| = 11.6619**

**Scalar product OA .OB = 86**

**Angle ∠ AOB = 23°50'19″ = 0.4161 rad**